Python Program for sum of squares of n natural numbers

In this article, we will learn to find the sum of the square of the first n number using the python program.

We find the sum of the square of positive numbers from 1 to nth using two methods:

• using for loop
• using mathematical formula

the sum of the square of n numbers:

1² + 2² + 3² + 4² + ....... + (n-1)² + n²

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Method 1: Using for loop

Program

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# Sum of the square of positive numbers from 1 to nth using forloop
n = int(input("Enter nth number: "))
sum = 0

for i in range(1,n+1):
    sum = sum + (i*i)

print("Sum of the square of the number from 1 to",n,"is: ",sum)

# Sum of the square of positive numbers from of nth using forloop - docodehere.com

Output

Enter nth number: 10
Sum of the square of the number from 1 to 10 is:  385

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Method 2: Using Mathematical formula

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# Sum of the square of positive numbers from 1 to nth without forloop
n = int(input("Enter nth number: "))

print((n * (n + 1) / 2) * (2 * n + 1) / 3)

# Sum of the square of positive numbers from of nth without forloop - docodehere.com

Enter nth number: 2
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